{"id":6102,"date":"2012-01-25T11:36:37","date_gmt":"2012-01-25T11:36:37","guid":{"rendered":"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/?p=6102"},"modified":"2013-01-21T14:54:42","modified_gmt":"2013-01-21T14:54:42","slug":"secrets-of-a-university-tutor-dissection-of-a-reaction-mechanism","status":"publish","type":"post","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=6102","title":{"rendered":"Secrets of a university tutor: dissection of a reaction mechanism."},"content":{"rendered":"<div class=\"kcite-section\" kcite-section-id=\"6102\">\n<p>Its a bit like a jigsaw puzzle in reverse, finding out to disassemble a chemical reaction into the pieces it is made from, and learning the rules that such reaction jigsaws follow. The following takes about 45-50 minutes to follow through with a group of students.<\/p>\n<p style=\"text-align: center;\"><a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6103\" title=\"pericyclic-tutorial\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial.svg\" alt=\"\" width=\"433\" height=\"106\" \/><\/a><\/p>\n<p>The problem is initially posed as the above (ignore the wavy bonds for now). The challenge is to identify the basic components that the reaction is built from and the rules these follow. It can be usefully salami-sliced as follows<\/p>\n<ol>\n<li>You are told the puzzle may consist of one or more (consecutive) pericyclic reactions. This should load up in your mind (from lecture notes) the various basic types of such reactions (the basic shapes of the jigsaw puzzle if you like).<\/li>\n<li>Rules from other areas of chemistry may be needed. Thus from your knowledge of the chemistry of benzene and its aromaticity, you need to remind yourself that there are two resonance forms (the Kekule forms) which are entirely equivalent. Problems such as the above may however be posed using either one or both of these forms. We will find out if this matters or not shortly.<\/li>\n<li>We need to clearly identify exactly what changes when the reaction occurs. To do this, it is useful to number what you think might be the key atoms.<br \/>\n<a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial1.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6105\" title=\"pericyclic-tutorial1\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial1.svg\" alt=\"\" width=\"433\" height=\"119\" \/><\/a><\/li>\n<li>Notice that some atoms are not numbered. It keeps things simple, but in fact numbering them all will not do any damage. The atoms not numbered are the methyl groups (it does seem as if they emerge from the reaction unchanged) and the benzo group on the left. Only time will tell if this scheme needs changing.<\/li>\n<li>And now we are in a position to create a checklist of changes that occur during the reaction.\n<ol>\n<li>A \u03c3-bond between 1-6 clearly forms<\/li>\n<li>A \u03c0-bond between 5-6 decreases to a \u03c3<\/li>\n<li>The\u00a0\u03c0-bonds in the (un-numbered) benzo group rotate. We recognise this as a benzene resonance rather than a (pericyclic) reaction.<\/li>\n<li>And now for the elephant in the room, the atoms that we (as chemists) know are there, but which are not explicitly shown. These are the hydrogens. We know a rule for this, which is that any structure shown without hydrogens is assumed to have as many attached as are required to achieve a four valent carbon. This is in fact a fuzzy rule, because some carbons can be divalent (carbenes) and some trivalent (carbocations). Normally the former have a <span style=\"font-size: large;\"><strong>:<\/strong><\/span> glyph appended to them, and the latter a <strong><span style=\"font-size: large;\">+<\/span><\/strong> charge, and we can see neither here so our rule stands. Time to count the elephants, and to draw the significant hydrogens explicitly (drawing them all would only clutter). We only select those hydrogens that appear to have moved during the reaction. Thus:<a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial2.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6106\" title=\"pericyclic-tutorial2\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial2.svg\" alt=\"\" width=\"361\" height=\"95\" \/><\/a><\/li>\n<li>A \u03c3-bond between 5-7 clearly forms<\/li>\n<li>A \u03c3-bond between 1-7 clearly breaks<\/li>\n<\/ol>\n<\/li>\n<li>We have four significant bonds that change, 1-6, 5-6, 5-7 and 1-7. The task now is to partition them into groups that might correspond to one of the basic types of pericyclic reaction, and these tend to be defined by how many\u00a0\u03c3-bonds make or break during the reaction\n<ol>\n<li>Thus an electrocyclic reaction either forms or breaks just one\u00a0\u03c3-bond<\/li>\n<li>A cycloaddition forms two (or more)\u00a0\u03c3-bonds and its reverse, a cyclo-elimination breaks two (or more)\u00a0\u03c3-bonds<\/li>\n<li>A sigmatropic reaction forms one \u03c3-bond and breaks another.<\/li>\n<li>Ene reactions break at least one \u03c3-bond and form at least one other, but in unequal numbers that distinguish them from a sigmatropic reaction.<\/li>\n<\/ol>\n<\/li>\n<li>Juggling with these pieces soon reveals that items 5.5 and 5.6 above can comprise a sigmatropic reaction, and that item 5.1 above constitutes an electrocyclic reaction. Item 5.2 above, involving only a \u03c0-bond is not counted.<\/li>\n<li>The next task is to decide which comes first! To do this, we need to again recollect carbon tetravalency, and the sacrosanct need not to exceed it. Clearly forming the 1-6 bond as our first action would violate this rule by creating a pentavalent carbon atom. So this leaves <strong>5-7\/1-7<\/strong> as our first action, which is going to be a sigma tropic reaction.<\/li>\n<li>We might recognise at this point that 5-7\/1-7 share a common atom (<strong>7<\/strong>). We can probably pencil in that this sigma tropic reaction is going to be of the type [1,?] from this observation. From the numbering above (which in fact was deliberately chosen to achieve this effect) we infer that hydrogen 7 moves along a chain of 5 carbon atoms, and so our nomenclature is complete; it is going to be a [1,5] hydrogen migration or sigmatropic shift. Had the numbering been different, we would have had to spot that the non-common bonds differed by five atoms.<\/li>\n<li>The arrow pushing to achieve this transformation is shown below. Notice that the arrows rotate anti-clockwise. It is a feature of pericyclic reactions that it does not matter which clock-direction they rotate in (mostly). Hence pushing them the other way would achieve exactly the same result.<a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial3.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6109\" title=\"pericyclic-tutorial3\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial3.svg\" alt=\"\" width=\"406\" height=\"107\" \/><\/a><\/li>\n<li>This brings a surprise; we needed five arrows, or ten electrons. Is that a unique solution? Well no. Had we remembered point 5.3 above, then another initial resonance form for the benzo-ring is possible, and this form requires us to push only three arrows, or six electrons.<a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial4.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6110\" title=\"pericyclic-tutorial4\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial4.svg\" alt=\"\" width=\"406\" height=\"107\" \/><\/a><\/li>\n<li>Is there a common factor between 6 and 10 electrons? Yes, it is the famous H\u00fcckel aromaticity <strong>4n+2 rule<\/strong>, for which n =1 or 2. So we get the result we really wanted, which is does not matter which of the two resonance forms for the benzo group we start with, we end up with arrow pushing that either way merely conforms to the 4n+2 rule. In other words, the transition state for this first reaction is <strong>aromatic<\/strong>. The stereochemistry implied by this result is going to be deferred to a second tutorial on this topic (and this is where the wavy lines will also come in).<\/li>\n<li>There is another observation we can make. The product of the [1,5] sigmatropic hydrogen shift no longer carries an aromatic ring on the left. We might infer that it will only be a transient intermediate, and will be very inclined to restore the aromaticity at the first opportunity.<\/li>\n<li>We are now in a position to create the 1-6 bond without violating the valency of either atom.<a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial5.svg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter  wp-image-6112\" title=\"pericyclic-tutorial5\" src=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2012\/01\/pericyclic-tutorial5.svg\" alt=\"\" width=\"355\" height=\"110\" \/><\/a><\/li>\n<li>The arrows shown above are two (black) to which can be followed either one more (green) or three more (red), making two possibilities carrying either 6 or 10 electrons. Again, both conform to the 4n+2 rule and so it does not matter which set is followed; the electrocyclic reaction will have an aromatic transition state (again we ignore stereochemistry for the time being).<\/li>\n<li>And hey, we have also recovered the aromaticity of our benzo group on the left.<\/li>\n<\/ol>\n<div>Well, it is now time to finish up this first tutorial on the topic. In <a href=\"http:\/\/www.ch.imperial.ac.uk\/rzepa\/blog\/?p=6124\" target=\"_blank\">the follow up<\/a>, I will show these aromatic transition state I have referred to here, and also include discussion of the stereochemistry.<\/div>\n<p>&nbsp;<\/p>\n<!-- kcite active, but no citations found -->\n<\/div> <!-- kcite-section 6102 -->","protected":false},"excerpt":{"rendered":"<p>Its a bit like a jigsaw puzzle in reverse, finding out to disassemble a chemical reaction into the pieces it is made from, and learning the rules that such reaction jigsaws follow. The following takes about 45-50 minutes to follow through with a group of students. The problem is initially posed as the above (ignore [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"activitypub_content_warning":"","activitypub_content_visibility":"","activitypub_max_image_attachments":5,"activitypub_interaction_policy_quote":"anyone","activitypub_status":"","footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2}},"categories":[],"tags":[984,2650,843,373],"ppma_author":[2661],"class_list":["post-6102","post","type-post","status-publish","format-standard","hentry","tag-chemical-reaction","tag-pericyclic","tag-reaction-mechanism","tag-tutorial-material"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Secrets of a university tutor: dissection of a reaction mechanism. - Henry Rzepa&#039;s Blog<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=6102\" \/>\n<meta property=\"og:locale\" content=\"en_GB\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Secrets of a university tutor: dissection of a reaction mechanism. - Henry Rzepa&#039;s Blog\" \/>\n<meta property=\"og:description\" content=\"Its a bit like a jigsaw puzzle in reverse, finding out to disassemble a chemical reaction into the pieces it is made from, and learning the rules that such reaction jigsaws follow. 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Here I revisit this reaction in which a small change is applied to the atoms\u2026","rel":"","context":"In &quot;Interesting chemistry&quot;","block_context":{"text":"Interesting chemistry","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?cat=4"},"img":{"alt_text":"","src":"https:\/\/i0.wp.com\/www.ch.ic.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2018\/12\/imine2.gif?resize=350%2C200&ssl=1","width":350,"height":200},"classes":[]},{"id":23281,"url":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=23281","url_meta":{"origin":6102,"position":1},"title":"The Stevens rearrangement: how history gives us new insights.","author":"Henry Rzepa","date":"January 29, 2021","format":false,"excerpt":"In a recent post, I told the story of how in the early 1960s, Robert Woodward had encountered an unexpected stereochemical outcome to the reaction of a hexatriene, part of his grand synthesis of vitamin B12. He had constructed a model of the reaction he wanted to undertake, perhaps with\u2026","rel":"","context":"In &quot;Historical&quot;","block_context":{"text":"Historical","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?cat=565"},"img":{"alt_text":"","src":"https:\/\/i0.wp.com\/www.ch.ic.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2021\/01\/sden.jpg?resize=350%2C200&ssl=1","width":350,"height":200},"classes":[]},{"id":5716,"url":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=5716","url_meta":{"origin":6102,"position":2},"title":"A modern take on pericyclic sigmatropic migrations.","author":"Henry Rzepa","date":"November 29, 2011","format":false,"excerpt":"Another common type of pericyclic reaction is the migration of hydrogen or carbon along a conjugated chain, as in the [1,3] migration of a carbon as shown below. As before, I explore the stereochemistry of the thermal and photochemical reactions. The reaction is known to proceed thermally\u00a0with inversion of configuration\u2026","rel":"","context":"In \"pericyclic\"","block_context":{"text":"pericyclic","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?tag=pericyclic"},"img":{"alt_text":"","src":"https:\/\/i0.wp.com\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2011\/11\/s.gif?resize=350%2C200","width":350,"height":200},"classes":[]},{"id":22774,"url":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=22774","url_meta":{"origin":6102,"position":3},"title":"Trimerous pericyclic reactions.","author":"Henry Rzepa","date":"October 8, 2020","format":false,"excerpt":"I occasionally spot an old blog that emerges, if only briefly, as \"trending\". In this instance, only the second blog I ever wrote here, way back in 2009 as a follow up to this article. With something of that age, its always worth revisiting to see if any aspect needs\u2026","rel":"","context":"In &quot;Curly arrows&quot;","block_context":{"text":"Curly arrows","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?cat=2327"},"img":{"alt_text":"","src":"https:\/\/i0.wp.com\/www.ch.ic.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2020\/10\/10-1024x671.jpg?resize=350%2C200&ssl=1","width":350,"height":200},"classes":[]},{"id":8426,"url":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=8426","url_meta":{"origin":6102,"position":4},"title":"A pericyclic dichotomy.","author":"Henry Rzepa","date":"November 30, 2012","format":false,"excerpt":"A dichotomy is a division into two mutually exclusive, opposed, or contradictory groups. Consider the reaction below. The bicyclic pentadiene on the left could in principle open on heating to give the monocyclic [12]-annulene (blue or red)\u00a0via what is called an electrocyclic reaction as either a six (red) or eight\u2026","rel":"","context":"In \"M\u00f6bius\"","block_context":{"text":"M\u00f6bius","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?tag=mobius"},"img":{"alt_text":"","src":"","width":0,"height":0},"classes":[]},{"id":11856,"url":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?p=11856","url_meta":{"origin":6102,"position":5},"title":"Three-for-one: a pericyclic brain teaser.","author":"Henry Rzepa","date":"January 12, 2014","format":false,"excerpt":"A game one can play with pericyclic reactions is to ask students to identify what type a given example is. So take for example the reaction below. The alternatives are: A cyclo-elimination reaction (red arrows). Two concurrent electrocyclic ring openings (blue and magenta arrows) Two consecutive electrocyclic ring openings Or\u2026","rel":"","context":"In &quot;Interesting chemistry&quot;","block_context":{"text":"Interesting chemistry","link":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/?cat=4"},"img":{"alt_text":"p34c","src":"https:\/\/i0.wp.com\/www.ch.imperial.ac.uk\/rzepa\/blog\/wp-content\/uploads\/2014\/01\/2%2B2-2nd.gif?resize=350%2C200","width":350,"height":200},"classes":[]}],"jetpack_likes_enabled":false,"authors":[{"term_id":2661,"user_id":1,"is_guest":0,"slug":"admin","display_name":"Henry Rzepa","avatar_url":"https:\/\/secure.gravatar.com\/avatar\/897b6740f7f599bca7942cdf7d7914af5988937ae0e3869ab09aebb87f26a731?s=96&d=blank&r=g","0":null,"1":"","2":"","3":"","4":"","5":"","6":"","7":"","8":""}],"_links":{"self":[{"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/posts\/6102","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6102"}],"version-history":[{"count":18,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/posts\/6102\/revisions"}],"predecessor-version":[{"id":9270,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=\/wp\/v2\/posts\/6102\/revisions\/9270"}],"wp:attachment":[{"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6102"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6102"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6102"},{"taxonomy":"author","embeddable":true,"href":"https:\/\/www.ch.ic.ac.uk\/rzepa\/blog\/index.php?rest_route=%2Fwp%2Fv2%2Fppma_author&post=6102"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}